问题描述
如果我的标题不清楚,这里是我所说的一个例子.
If my title isn't clear here's an example of what I am talking about.
假设我有一张如下所示的表格:
Let's say I have a table that looks like this:
+----+------+----+----+---------+-------+---------+-------+
| ID | Time | X | Y | X_START | X_END | Y_START | Y_END |
+----+------+----+----+---------+-------+---------+-------+
| 1 | 0 | 8 | 6 | 6 | 10 | 4 | 8 |
| 2 | 0 | 20 | 10 | 18 | 22 | 8 | 12 |
| 3 | 1 | 8 | 8 | 6 | 10 | 6 | 10 |
| 4 | 1 | 10 | 24 | 8 | 12 | 22 | 26 |
+----+------+----+----+---------+-------+---------+-------+
如果我将此查询应用于表:
If I apply this query to the table:
WITH
cte1 AS (SELECT *,
DENSE_RANK() OVER (ORDER BY TIME) AS DENSE_RANK
FROM data
ORDER BY TIME)
SELECT * FROM cte1
我明白了:
+----+------+----+----+---------+-------+---------+-------+------------+
| ID | Time | X | Y | X_START | X_END | Y_START | Y_END | DENSE_RANK |
+----+------+----+----+---------+-------+---------+-------+------------+
| 1 | 0 | 8 | 6 | 6 | 10 | 4 | 8 | 1 |
| 2 | 0 | 20 | 10 | 18 | 22 | 8 | 12 | 1 |
| 3 | 1 | 8 | 8 | 6 | 10 | 6 | 10 | 2 |
| 4 | 1 | 10 | 24 | 8 | 12 | 22 | 26 | 2 |
+----+------+----+----+---------+-------+---------+-------+------------+
现在我要做的是过滤掉 X 在 X_START - X_END 范围内且 Y 在 Y_START - Y_END 范围内且 DENSE_RANK 为 n-1 的任何行
Now what I want to do is filter out any rows where X is within the range X_START - X_END AND Y is within the range Y_START - Y_END AND DENSE_RANK is n-1
所以我想要一个看起来像这样的结果:
so I'd like a result that looks like this:
+----+------+----+----+---------+-------+---------+-------+------------+
| ID | Time | X | Y | X_START | X_END | Y_START | Y_END | DENSE_RANK |
+----+------+----+----+---------+-------+---------+-------+------------+
| 1 | 0 | 8 | 6 | 6 | 10 | 4 | 8 | 1 |
| 2 | 0 | 20 | 10 | 18 | 22 | 8 | 12 | 1 |
| 4 | 1 | 10 | 24 | 8 | 12 | 22 | 26 | 2 |
+----+------+----+----+---------+-------+---------+-------+------------+
我对 SQL 很陌生,所以我不太确定如何去做.提前感谢您的所有帮助!
I am pretty new to SQL so I am not too sure on how to go about this. Thank you for all help in advance!
推荐答案
使用MIN()
窗口函数来识别每个Time
的最小ID
代码> 以便在所有其他条件也满足的情况下排除该行:
Use MIN()
window function to identify the minimum ID
for each Time
so that you can exclude that row if all the other conditions are satisfied too:
WITH cte AS (
SELECT *,
DENSE_RANK() OVER (ORDER BY TIME) AS `DENSE_RANK`,
MIN(ID) OVER (PARTITION BY TIME) min_id
FROM data
)
SELECT ID, Time, X, Y, X_START, X_END, Y_START, Y_END, `DENSE_RANK`
FROM cte
WHERE `DENSE_RANK` = 1
OR NOT (ID = min_id AND X BETWEEN X_START AND X_END AND Y BETWEEN Y_START AND Y_END)
ORDER BY `DENSE_RANK`, ID;
请参阅演示.
这篇关于SQL使用N-1 Dense Rank过滤掉密集秩N中的行 Mysql的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!