本文介绍了自引用表 (Oracle) 上的 SQL 递归查询的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
假设我有这个样本数据:
Lets assume I have this sample data:
| Name | ID | PARENT_ID |
-----------------------------
| a1 | 1 | null |
| b2 | 2 | null |
| c3 | 3 | null |
| a1.d4 | 4 | 1 |
| a1.e5 | 5 | 1 |
| a1.d4.f6 | 6 | 4 |
| a1.d4.g7 | 7 | 4 |
| a1.e5.h8 | 8 | 5 |
| a2.i9 | 9 | 2 |
| a2.i9.j10| 10 | 9 |
我想选择从 accountId = 1 开始的所有记录,所以预期的结果是:
I would like to select all records start from accountId = 1, so the expected result would be:
| Name | ID | PARENT_NAME | PARENT_ID |
-------------------------------------------
| a1 | 1 | null | null |
| a1.d4 | 4 | a1 | 1 |
| a1.e5 | 5 | a1 | 1 |
| a1.d4.f6 | 6 | a1.d4 | 4 |
| a1.d4.g7 | 7 | a1.d4 | 4 |
| a1.e5.h8 | 8 | a1.e5 | 5 |
我目前能够进行递归选择,但是我无法从父引用访问数据,因此我无法返回 parent_name.我使用的代码是(适用于简单的例子):
I am currently able to make the recursive select, but then I can't access the data from the parent reference, hence I can't return parent_name. The code I'm using is (adapted to the simplistic example):
SELECT id, parent_id, name
FROM tbl
START WITH id = 1
CONNECT BY PRIOR id = parent_id
我应该使用什么 SQL 来进行上述检索?
What SQL should I be using to the mentioned above retrieval?
未来搜索者的额外关键词:SQL 选择由同一个表中的父键表示的分层数据
推荐答案
使用:
SELECT t1.id,
t1.parent_id,
t1.name,
t2.name AS parent_name,
t2.id AS parent_id
FROM tbl t1
LEFT JOIN tbl t2 ON t2.id = t1.parent_id
START WITH t1.id = 1
CONNECT BY PRIOR t1.id = t1.parent_id
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