问题描述
我在留言簿中有一张包含用户评论的表格.列是:id、user_id、title、comment、timestamp.
I have a table with user comments in a guestbook. Columns are: id, user_id, title, comment, timestamp.
我需要为每个用户选择最新的行.我曾尝试使用 group by 执行此操作,但尚未对其进行管理,因为我无法在按 user_id 分组的同一查询中选择任何其他内容:
I need to select the latest row for each user. I have tried to do this with group by but havent managed it because i cant select anything else in the same query where i group by user_id:
SELECT user_id, MAX(ts) FROM comments GROUP BY user_id
例如在这个查询中,我不能添加到选择列 id、tilte 和 comment.这怎么办?
for example in this query i cant add to also select columns id, tilte and comment. How can this be done?
推荐答案
可以使用解析函数
SELECT *
FROM (SELECT c.*,
rank() over (partition by user_id order by ts desc) rnk
FROM comments c)
WHERE rnk = 1
根据您希望如何处理关系(如果可以有两行具有相同的 user_id
和 ts
),您可能需要使用 row_number
或 dense_rank
函数而不是 rank
.如果有平局,rank
将允许多行排在第一位.如果有平局,row_number
将任意返回一行.对于并列第一的行,dense_rank
的行为类似于 rank
,但会认为下一行是第二行,而不是第三行,假设两行并列第一.
Depending on how you want to handle ties (if there can be two rows with the same user_id
and ts
), you may want to use the row_number
or dense_rank
function rather than rank
. rank
would allow multiple rows to be first if there was a tie. row_number
would arbitrarily return one row if there was a tie. dense_rank
would behave like rank
for the rows that tied for first but would consider the next row to be second rather than third assuming two rows tie for first.
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