问题描述

我使用的是 MS SQL 2008 R2，有三个具有以下架构的表:

I'm using MS SQL 2008 R2, have three tables with following schema:

表 1:包含每个工人的轮班信息

Table 1: Contains workshift info for each worker

CREATE TABLE workshift (
[ws_id] [bigint] NOT NULL,
[start_date] [datetime] NOT NULL,
[end_date] [datetime] NOT NULL,
[worker_id] [bigint] NOT NULL
)

INSERT INTO workshift VALUES (1, '2012-08-20 08:30:00', '2012-08-20 14:30:00', 1)
INSERT INTO workshift VALUES (2, '2012-08-20 14:30:00', '2012-08-20 22:30:00', 2)

表 2:包含货币面额

CREATE TABLE currency_denom (
[cd_id] [decimal](7, 2) NOT NULL,
[name] [nchar](100) NOT NULL
)

INSERT INTO currency_denom VALUES (1, '100.00')
INSERT INTO currency_denom VALUES (2, '50.00')
INSERT INTO currency_denom VALUES (3, '20.00')
INSERT INTO currency_denom VALUES (4, '10.00')
INSERT INTO currency_denom VALUES (5, '5.00')
INSERT INTO currency_denom VALUES (6, '1.00')

表 3:包含工人在每个班次中收到的每种面额的数量

Table 3: Contains the quantity of each denomination the worker has received in every workshift

CREATE TABLE currency_by_workshift (
[cd_id] [decimal](7, 2) NOT NULL,
[ws_id] [bigint] NOT NULL,
[qty] [int] NOT NULL
)

INSERT INTO currency_by_workshift VALUES (1, 1, 1)
INSERT INTO currency_by_workshift VALUES (2, 1, 2)
INSERT INTO currency_by_workshift VALUES (3, 1, 2)
INSERT INTO currency_by_workshift VALUES (2, 2, 3)
INSERT INTO currency_by_workshift VALUES (4, 2, 4)
INSERT INTO currency_by_workshift VALUES (5, 2, 2)

我需要获取列而不是行中的currency_by_workshift 值以及轮班值，即:

I need to get the currency_by_workshift values in columns instead of rows, along with the workshift values, that is:

workshift |     workshift       |     workshift       | 100.00 | 50.00 | 20.00 | 10.00 | 5.00 | 1.00 
  ws_id   |     start_date      |     end_date        |        |       |       |       |      | 

    1     | 2012-08-20 08:30:00 | 2012-08-20 14:30:00 |    1   |   2   |   2   |   0   |   0  |   0
    2     | 2012-08-20 14:30:00 | 2012-08-20 22:30:00 |    0   |   2   |   0   |   4   |   2  |   0

我无法使用 case 来计算每种货币面额的数量，因为它们是可配置的，如果添加了新面额，则应修改查询.如果使用 PIVOT 功能也一样，还是我错了?

I'm not able to use a case to count quantities for each currency denomination because they are configurable, if a new denomination is added, the query should be modified. Same applies if using PIVOT function, or I'm wrong?

我怎样才能以这种方式获取信息?

How can I get the info that way?

推荐答案

您尝试执行的操作称为 PIVOT.有两种方法可以做到这一点，使用静态枢轴或动态枢轴.

What you are trying to do is called a PIVOT. There are two ways to do this, either with a Static Pivot or a Dynamic Pivot.

Static Pivot - 是您将行的值硬编码以转换为列的地方(参见 SQL Fiddle with Demo):

Static Pivot - is where you will hard-code the values of the rows to transform to columns (See SQL Fiddle with Demo):

select ws_id,
  start_date,
  end_date,
  IsNull([100.00], 0) [100.00],
  IsNull([50.00], 0) [50.00],
  IsNull([20.00], 0) [20.00],
  IsNull([10.00], 0) [10.00],
  IsNull([5.00], 0) [5.00],
  IsNull([1.00], 0) [1.00]
from 
(
  select ws.ws_id,
    ws.start_date,
    ws.end_date,
    cd.name,
    cbw.qty
  from workshift ws
  left join currency_by_workshift cbw
    on ws.ws_id = cbw.ws_id
  left join currency_denom cd
    on cbw.cd_id = cd.cd_id
) x
pivot
(
  sum(qty)
  for name in ([100.00], [50.00], [20.00], [10.00], [5.00], [1.00])
) p

动态数据透视是在运行时确定列的地方(参见 SQL Fiddle with Demo):

Dynamic pivot is where the columns are determined at run-time (see SQL Fiddle with Demo):

DECLARE @cols AS NVARCHAR(MAX),
    @query  AS NVARCHAR(MAX),
    @colsPivot AS NVARCHAR(MAX)

select @colsPivot = 
  STUFF((SELECT ', IsNull(' + QUOTENAME(rtrim(name)) +', 0) as ['+ rtrim(name)+']' 
                    from currency_denom
                   GROUP BY name
                   ORDER BY cast(name as decimal(10, 2)) desc
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')

select @cols = STUFF((SELECT distinct ', ' + QUOTENAME(name)
                    from currency_denom
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')


set @query 
      = 'SELECT ws_id, start_date, end_date,' + @colsPivot + ' from 
         (
            select ws.ws_id,
              ws.start_date,
              ws.end_date,
              cd.name,
              cbw.qty
            from workshift ws
            left join currency_by_workshift cbw
              on ws.ws_id = cbw.ws_id
            left join currency_denom cd
              on cbw.cd_id = cd.cd_id
         ) x
         pivot 
         (
            sum(qty)
            for name in (' + @cols + ')
         ) p '

execute(@query)

两个版本都会产生相同的结果.

Both versions will produce the same results.

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