本文介绍了MySQL IN 和 LIKE的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我将如何使用带有 like 的 IN 表?这样我就可以在其中使用 % 了吗?我的意思是:
How would I use a IN table with like? So that I could use % in them? By in I mean:
SELECT fields
FROM table
WHERE age = "50"
AND name IN ("tim", "bob", "nancy", "john");
我已经试过了:
SELECT fields
FROM table
WHERE age = "50"
AND name LIKE ("2010-09-17%", "2010-09-16%")
但它给出了错误操作数应该包含 1 列"
But it gave the error "Operand should contain 1 column(s)"
推荐答案
您可以使用多个 LIKE 表达式:
You can use a number of LIKE expressions:
SELECT fields
FROM table
WHERE age = "50"
AND (
name LIKE "2010-09-17%"
OR name LIKE "2010-09-16%"
);
或者你可以使用正则表达式:
or you can use a regex:
SELECT fields
FROM table
WHERE age = "50"
AND name REGEXP "2010-09-17.*|2010-09-16.*";
或者，巧妙地
SELECT fields
FROM table
WHERE age = "50"
AND name REGEXP "2010-09-1(6|7).*";
这篇关于MySQL IN 和 LIKE的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！
本站部分内容来源互联网,如果有图片或者内容侵犯您的权益请联系我们删除！