问题描述
我有一张像这样的桌子
CREATE TABLE `time_table` (
`id` INT(10) NOT NULL AUTO_INCREMENT,
`creationDate` DATETIME NOT NULL,
PRIMARY KEY (`id`)
)
我基本上将某些记录的创建时间存储在表中.我知道如果我想获得以 15 分钟为间隔创建的记录的计数，我将使用类似这样的方法
I basically store the creation time of certain records in the table. I know if I want to get a count of the records that were created in 15 mins interval I will use something like this
SELECT FLOOR(UNIX_TIMESTAMP(creationDate)/900) AS t,
COUNT(*) FROM time_table
GROUP BY t
这给了我这样的东西
t COUNT(*)
1434187 1
1434188 3
1434189 2
1434190 2
我如何理解第一列?如果我想让它向我展示类似
How do I make sense of the first column? If I want it to show me something like
t COUNT(*)
2:00pm - 2:15pm 1
2:15pm - 2:30pm 3
2:30pm - 2:45pm 2
2:45pm - 3:00pm 2
我知道通过一些操作，我可以让 1434187 在下午 2:15 出现.即使那可能是一个好的开始......然后通过一些逻辑我可以展示整个时期.谢谢！
I understand that with some manipulation I could get 1434187 to show up at 2:15pm. Even that might be a good start....then with some logic I could show the entire period. Thanks!
推荐答案
一种方法是只使用 > 和 < 以获得范围内的所有内容，但您可能会发现这更简单:
One way is to just use > and < in order to get everything within a range, but you may find this to be simpler:
SELECT ...
GROUP BY ( 4 * HOUR( thistime ) + FLOOR( MINUTE( thistime ) / 15 ))
来自http://forums.mysql.com/read.php?10,202789,202807
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