本文介绍了当分配给命令的连接处于挂起的本地传输状态时,ExecuteReader 要求命令具有事务的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我必须在两个表中插入单个事务,必须执行的查询如下.其次在 SqlDataReader read = comm.ExecuteReader();
i have to insert in two tables with single transaction, query which have to implement are below. secondly getting exception at SqlDataReader read = comm.ExecuteReader();
public void SqlExecuteNonQuery(Customer obj)
{
//string query = "DECLARE @_customerID int ";
string query1 = "INSERT INTO customer (customerName,customerSex,Email) VALUES ('" + obj.name + "','" + obj.sex + "','" + obj.Email + "') ";
//string query2 = "SET @_customerID =@@identity ";
string query3 = "INSERT INTO customerDetails(customerID,customerAddress,customerPhone) VALUES (" + obj.id + ",'" + obj.address + "','" + obj.phone + "') ";
string CS = ConnectionName;
using (SqlConnection conn = new SqlConnection(CS))
{
conn.Open();
using (SqlCommand command = new SqlCommand("SELECT Email FROM Customer where Email ='" + obj.Email + "'", conn))
{
SqlDataReader reader = command.ExecuteReader();
try
{
if (reader.Read())
{
throw new Exception("User already exist for the email");
}
else
{
reader.Close();
using (SqlCommand cmd = GetCommand(query1, conn))
{
SqlTransaction transaction;
transaction = conn.BeginTransaction();
try
{
cmd.Transaction = transaction;
cmd.ExecuteNonQuery();
using (SqlCommand comm = new SqlCommand("Select customerID from Customer where email = '" + obj.Email + "'", conn))
{
SqlDataReader read = comm.ExecuteReader();
try
{
while (read.Read())
{
obj.id = (int)read[0];
}
using (SqlCommand cmd1 = GetCommand(query3, conn))
{
try
{
cmd1.ExecuteNonQuery();
}
catch (Exception ex1)
{
Console.WriteLine("Comit Exception Type: {0}", ex1.GetType());
Console.WriteLine("error in inserting - {0}", ex1.Message);
try
{
transaction.Rollback();
}
catch (Exception ex2)
{
Console.WriteLine("RollBack Exception Type: {0}", ex2.GetType());
Console.WriteLine("Message: {0}", ex2.Message);
}
}
}
transaction.Commit();
Console.WriteLine("Successfull transaction");
}
catch (Exception ex)
{
Console.WriteLine("Error type:", ex.GetType());
Console.WriteLine("Message:", ex.Message);
}
finally {
read.Close();
}
}
}
catch (Exception ex)
{
Console.WriteLine("Comit Exception Type: {0}", ex.GetType());
Console.WriteLine("error in inserting - {0}", ex.Message);
try
{
transaction.Rollback();
}
catch (Exception ex2)
{
Console.WriteLine("RollBack Exception Type: {0}", ex2.GetType());
Console.WriteLine("Message: {0}", ex2.Message);
}
}
finally
{
transaction.Dispose();
}
}
}
}
catch (Exception ex)
{
Console.WriteLine(ex.Message);
}
}
}
}
推荐答案
问题是您在与 cmd 相同的连接上执行 cmd1,因此该连接上有一个打开的事务,但您没有设置 cmd1.Transaction ... 所以解决方案是
problem is you execute cmd1 on the same connection as cmd so there is an open transaction on that connection but you don't set cmd1.Transaction ... so solution would be to
cmd1.Transaction = transaction;
之前
cmd1.ExecuteNonQuery();
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