本文介绍了如何同时遍历两个 IEnumerables?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有两个枚举:IEnumerable<A>list1
和 IEnumerable<B>列表2
.我想同时遍历它们,例如:
I have two enumerables: IEnumerable<A> list1
and IEnumerable<B> list2
. I would like to iterate through them simultaneously like:
foreach((a, b) in (list1, list2))
{
// use a and b
}
如果它们不包含相同数量的元素,则应抛出异常.
If they don't contain the same number of elements, an exception should be thrown.
最好的方法是什么?
推荐答案
这是这个操作的一个实现,通常称为 Zip:
Here's an implementation of this operation, typically called Zip:
using System;
using System.Collections.Generic;
namespace SO2721939
{
public sealed class ZipEntry<T1, T2>
{
public ZipEntry(int index, T1 value1, T2 value2)
{
Index = index;
Value1 = value1;
Value2 = value2;
}
public int Index { get; private set; }
public T1 Value1 { get; private set; }
public T2 Value2 { get; private set; }
}
public static class EnumerableExtensions
{
public static IEnumerable<ZipEntry<T1, T2>> Zip<T1, T2>(
this IEnumerable<T1> collection1, IEnumerable<T2> collection2)
{
if (collection1 == null)
throw new ArgumentNullException("collection1");
if (collection2 == null)
throw new ArgumentNullException("collection2");
int index = 0;
using (IEnumerator<T1> enumerator1 = collection1.GetEnumerator())
using (IEnumerator<T2> enumerator2 = collection2.GetEnumerator())
{
while (enumerator1.MoveNext() && enumerator2.MoveNext())
{
yield return new ZipEntry<T1, T2>(
index, enumerator1.Current, enumerator2.Current);
index++;
}
}
}
}
class Program
{
static void Main(string[] args)
{
int[] numbers = new[] { 1, 2, 3, 4, 5 };
string[] names = new[] { "Bob", "Alice", "Mark", "John", "Mary" };
foreach (var entry in numbers.Zip(names))
{
Console.Out.WriteLine(entry.Index + ": "
+ entry.Value1 + "-" + entry.Value2);
}
}
}
}
如果只有一个序列用完值,要使其抛出异常,请更改 while 循环:
To make it throw an exception if just one of the sequences run out of values, change the while-loop so:
while (true)
{
bool hasNext1 = enumerator1.MoveNext();
bool hasNext2 = enumerator2.MoveNext();
if (hasNext1 != hasNext2)
throw new InvalidOperationException("One of the collections ran " +
"out of values before the other");
if (!hasNext1)
break;
yield return new ZipEntry<T1, T2>(
index, enumerator1.Current, enumerator2.Current);
index++;
}
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