问题描述

来自 C++ 背景，我习惯于将 const 关键字粘贴到函数定义中，以使对象以只读值传递.但是，我发现这在 C# 中是不可能的(如果我错了，请纠正我).经过一番谷歌搜索，我得出的结论是，制作只读对象的唯一方法是编写一个只有获取"属性的接口，然后将其传入.优雅，我必须说.

Coming from a C++ background, I'm used to sticking the const keyword into function definitions to make objects being passed in read-only values. However, I've found out that this is not possible in C# (please correct me if I'm wrong). After some Googling, I arrived at the conclusion that the only way to make a read-only object is to write an interface that only has 'get' properties and pass that in instead. Elegant, I must say.

public interface IFoo
{
  IMyValInterface MyVal{ get; }
}

public class Foo : IFoo
{
  private ConcreteMyVal _myVal;

  public IMyValInterface MyVal
  {
    get { return _myVal; }
  }
}

我会把它传递给:

public void SomeFunction(IFoo fooVar)
{
  // Cannot modify fooVar, Excellent!!
}

这很好.但是，在我的其余代码中，我想正常修改我的对象.向界面添加设置"属性会打破我的只读限制.我可以向 Foo(而不是 IFoo)添加一个set"属性，但签名需要一个接口而不是具体对象.我必须做一些选角.

This is fine. However, in the rest of my code, I would like to modify my object normally. Adding a 'set' property to the interface would break my read-only restriction. I can add a 'set' property to Foo (and not IFoo), but the signature expects an interface rather than a concrete object. I would have to do some casting.

// Add this to class Foo. Might assign null if cast fails??
set { _myVal = value as ConcreteMyVal; }

// Somewhere else in the code...
IFoo myFoo = new Foo;
(myFoo as Foo).MyFoo = new ConcreteMyVal();

有没有更优雅的方法来复制 const 或制作只读函数参数而不添加其他属性或函数?

Is there a more elegant way of replicating const or making read-only function parameters without adding another property or a function?

推荐答案

我认为您可能正在寻找一种解决方案，其中涉及两个接口，其中一个继承自另一个:

I think you may be looking for a solution involving two interfaces in which one inherits from the other:

public interface IReadableFoo
{
    IMyValInterface MyVal { get; }
}

public interface IWritableFoo : IReadableFoo
{
    IMyValInterface MyVal { set; }
}

public class Foo : IWritableFoo 
{
    private ConcreteMyVal _myVal;

    public IMyValInterface MyVal
    {
        get { return _myVal; }
        set { _myVal = value as ConcreteMyVal; }
    }
}

然后您可以声明其参数类型告诉"它是否计划更改变量的方法:

Then you can declare methods whose parameter type "tells" whether it plans on changing the variable or not:

public void SomeFunction(IReadableFoo fooVar)
{
    // Cannot modify fooVar, excellent!
}

public void SomeOtherFunction(IWritableFoo fooVar)
{
    // Can modify fooVar, take care!
}

这模仿了类似于 C++ 中的 constness 的编译时检查.正如 Eric Lippert 正确指出的那样，这与不变性不相同.但作为一名 C++ 程序员，我想你知道这一点.

This mimics compile-time checks similar to constness in C++. As Eric Lippert correctly pointed out, this is not the same as immutability. But as a C++ programmer I think you know that.

顺便说一句，如果将类中的属性类型声明为ConcreteMyVal并单独实现接口属性，则可以实现稍微更好的编译时检查:

By the way, you can achieve slightly better compile-time checking if you declare the type of the property in the class as ConcreteMyVal and implement the interface properties separately:

public class Foo : IWritableFoo 
{
    private ConcreteMyVal _myVal;

    public ConcreteMyVal MyVal
    {
        get { return _myVal; }
        set { _myVal = value; }
    }

    public IMyValInterface IReadableFoo.MyVal { get { return MyVal; } }
    public IMyValInterface IWritableFoo.MyVal
    {
        // (or use "(ConcreteMyVal)value" if you want it to throw
        set { MyVal = value as ConcreteMyVal; }
    }
}

这样，setter 只能在通过接口访问时抛出，而在通过类访问时不能.

This way, the setter can only throw when accessed through the interface, but not when accessed through the class.

这篇关于C# 的只读(类似“const")函数参数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！