问题描述
我正在开发一个允许使用 ASP.NET C# 将图像上传到服务器的系统.我正在处理图像,一切都很好.我设法找到一种方法来读取 Date Created EXIF 数据并将其解析为 DateTime.这也很好用.
I am developing a system that allows for an image to be uploaded to a server using ASP.NET C#. I am processing the image and all is working great. I have managed to find a method that reads the Date Created EXIF data and am parsing it as a DateTime. That works great too.
我现在正尝试从 EXIF 读取 GPS 数据.我想捕捉纬度和经度的数字.
I am now trying to read GPS data from the EXIF. I am wanting to capture the Latitude and Longitude figures.
我将此列表用作 EXIF 数据的参考(使用属性项的数字)http://www.exiv2.org/tags.html
I am using this list as a reference to the EXIF data (using the numbers for the property items) http://www.exiv2.org/tags.html
这是捕获创建日期的方法(有效).
Here is the method to capture the date created (which works).
public DateTime GetDateTaken(Image targetImg)
{
DateTime dtaken;
try
{
//Property Item 306 corresponds to the Date Taken
PropertyItem propItem = targetImg.GetPropertyItem(0x0132);
//Convert date taken metadata to a DateTime object
string sdate = Encoding.UTF8.GetString(propItem.Value).Trim();
string secondhalf = sdate.Substring(sdate.IndexOf(" "), (sdate.Length - sdate.IndexOf(" ")));
string firsthalf = sdate.Substring(0, 10);
firsthalf = firsthalf.Replace(":", "-");
sdate = firsthalf + secondhalf;
dtaken = DateTime.Parse(sdate);
}
catch
{
dtaken = DateTime.Parse("1956-01-01 00:00:00.000");
}
return dtaken;
}
下面是我对 GPS 做同样的尝试..
Below is my attempt at doing the same for GPS..
public float GetLatitude(Image targetImg)
{
float dtaken;
try
{
//Property Item 0x0002 corresponds to the Date Taken
PropertyItem propItem = targetImg.GetPropertyItem(2);
//Convert date taken metadata to a DateTime object
string sdate = Encoding.UTF8.GetString(propItem.Value).Trim();
dtaken = float.Parse(sdate);
}
catch
{
dtaken = 0;
}
return dtaken;
}
进入 sdate 的值为 "5 l d "
The value that's coming out and into sdate is "5 l d "
这是来自带有 GPS EXIF 数据的 iPhone 4 拍摄的图像.
And that is coming from an image that was taken by an iPhone 4 which does carry the GPS EXIF data.
我知道有一些课程可以做到这一点,但我更愿意自己编写 - 不过我愿意接受建议 :-)
I know there are classes out there that do this but would prefer to write my own - I am open to suggestions though :-)
提前致谢.
推荐答案
根据tomfanning 在上面发布的链接,属性项 0x0002 是表示为 PropertyTagTypeRational
的纬度.有理类型定义为...
According to the link posted above by tomfanning, property item 0x0002 is the latitude expressed as a PropertyTagTypeRational
. The rational type is defined as...
指定值数据成员是一个无符号长整数对数组.每对代表一个分数;第一个整数是分子,第二个整数是分母.
Specifies that the value data member is an array of pairs of unsigned long integers. Each pair represents a fraction; the first integer is the numerator and the second integer is the denominator.
当它实际上只是一系列字节时,您试图将其解析为字符串.根据上述,应该有 3 对 32 位无符号整数打包到该字节数组中,您可以使用以下方法检索:
You are trying to parse it as a string when it's actually just a series of bytes. According to the above, there should be 3 pairs of 32-bit unsigned integers packed into that byte array, which you can retrieve using the following:
uint degreesNumerator = BitConverter.ToUInt32(propItem.Value, 0);
uint degreesDenominator = BitConverter.ToUInt32(propItem.Value, 4);
uint minutesNumerator = BitConverter.ToUInt32(propItem.Value, 8);
uint minutesDenominator = BitConverter.ToUInt32(propItem.Value, 12);
uint secondsNumerator = BitConverter.ToUInt32(propItem.Value, 16);
uint secondsDenominator = BitConverter.ToUInt32(propItem.Value, 20);
在获得这些值后,您如何处理这些值是为了让您自己解决:) 文档是这样说的:
What you do with these values after you've got them is for you to work out :) Here's what the docs say:
纬度表示为三个有理值,分别给出度、分和秒.表示度、分、秒时,格式为dd/1、mm/1、ss/1.当使用度和分时,例如,分钟的小数部分最多保留两位小数,格式为 dd/1、mmmm/100、0/1.
Latitude is expressed as three rational values giving the degrees, minutes, and seconds respectively. When degrees, minutes, and seconds are expressed, the format is dd/1, mm/1, ss/1. When degrees and minutes are used and, for example, fractions of minutes are given up to two decimal places, the format is dd/1, mmmm/100, 0/1.
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