本文介绍了如何使用 DropDownList 的 SelectedIndexChanged 事件的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我的网络表单中有两个 DropDownList
,当我在第一个下拉列表中选择一个值时,我希望在第二个下拉列表中自动选择一个相关值.
I have two DropDownList
s in my webform and when I select a value in the first dropdownlist, I would like a related value to be automatically selected in the second dropdownlist.
这是我目前拥有的:
<table>
<tr>
<td>
<asp:Label ID="lbmanu" runat="server" Text="Furniture Manufacturer :
"></asp:Label>
</td>
<td>
<asp:DropDownList ID="ddmanu" runat="server"
DataSourceID="Sql_fur_model_manu"
DataTextField="manufacturer" DataValueField="manufacturer"
onselectedindexchanged="ddmanu_SelectedIndexChanged">
</asp:DropDownList>
<asp:SqlDataSource ID="Sql_fur_model_manu" runat="server"
ConnectionString="<%$ ConnectionStrings:conStr %>"
SelectCommand="SELECT DISTINCT [manufacturer] FROM
[furniture_manufacturer]">
</asp:SqlDataSource>
</td>
</tr>
<tr>
<td>
<asp:Label ID="lbtype" runat="server" Text="Furniture Type :
"></asp:Label>
</td>
<td>
<asp:DropDownList ID="ddtype" runat="server" AutoPostBack="True">
</asp:DropDownList>
</td>
</tr>
</table>
背后的代码:
protected void ddmanu_SelectedIndexChanged(object sender, EventArgs e)
{
string query = "select furniture from furniture_model where manufacturer='" +
ddmanu.SelectedValue.ToString() + "'";
con.Open();
cmd = new SqlCommand(query, con);
DataTable dt = Select(query);
cmd.ExecuteNonQuery();
ddtype.DataSource = dt;
ddtype.DataTextField = "manufacturer";
ddtype.DataValueField = "furniture";
ddtype.DataBind();
}
推荐答案
您应该将 AutoPostBack="true" 添加到 DropDownList1
You should add AutoPostBack="true" to DropDownList1
<asp:DropDownList ID="ddmanu" runat="server" AutoPostBack="true"
DataSourceID="Sql_fur_model_manu"
DataTextField="manufacturer" DataValueField="manufacturer"
onselectedindexchanged="ddmanu_SelectedIndexChanged">
</asp:DropDownList>
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