本文介绍了如何反序列化具有动态(数字)键名的子对象?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如何反序列化此 JSON 数据?100034"等键本质上是动态的.
How can I deserialize this JSON data? The keys "100034" etc. are dynamic in nature.
{
"users" : {
"100034" : {
"name" : "tom",
"state" : "WA",
"id" : "cedf-c56f-18a4-4b1"
},
"10045" : {
"name" : "steve",
"state" : "NY",
"id" : "ebb2-92bf-3062-7774"
},
"12345" : {
"name" : "mike",
"state" : "MA",
"id" : "fb60-b34f-6dc8-aaf7"
}
}
}
有没有一种方法可以直接访问具有名称、状态和 ID 的每个对象?
Is there a way I can directly access each object having name, state and Id?
推荐答案
对于属性名称可变的 JSON 对象,您可以使用 Dictionary
代替常规类,其中 T
是表示项目数据的类.
For JSON objects having property names which can vary, you can use a Dictionary<string, T>
in place of a regular class, where T
is a class representing the item data.
像这样声明你的类:
class RootObject
{
public Dictionary<string, User> users { get; set; }
}
class User
{
public string name { get; set; }
public string state { get; set; }
public string id { get; set; }
}
然后像这样反序列化:
RootObject obj = JsonConvert.DeserializeObject<RootObject>(json);
演示:
class Program
{
static void Main(string[] args)
{
string json = @"
{
""users"": {
""10045"": {
""name"": ""steve"",
""state"": ""NY"",
""id"": ""ebb2-92bf-3062-7774""
},
""12345"": {
""name"": ""mike"",
""state"": ""MA"",
""id"": ""fb60-b34f-6dc8-aaf7""
},
""100034"": {
""name"": ""tom"",
""state"": ""WA"",
""id"": ""cedf-c56f-18a4-4b1""
}
}
}";
RootObject root = JsonConvert.DeserializeObject<RootObject>(json);
foreach (string key in root.users.Keys)
{
Console.WriteLine("key: " + key);
User user = root.users[key];
Console.WriteLine("name: " + user.name);
Console.WriteLine("state: " + user.state);
Console.WriteLine("id: " + user.id);
Console.WriteLine();
}
}
}
输出:
key: 10045
name: steve
state: NY
id: ebb2-92bf-3062-7774
key: 12345
name: mike
state: MA
id: fb60-b34f-6dc8-aaf7
key: 100034
name: tom
state: WA
id: cedf-c56f-18a4-4b1
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