对属性的 Json DeserializeObject 运行转换

running a transformation on a Json DeserializeObject for a property(对属性的 Json DeserializeObject 运行转换)
本文介绍了对属性的 Json DeserializeObject 运行转换的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

假设一个json字符串如下:

Assuming a json string like the following:

string json = '{"string_property":"foo_bar", ... other objects here ...}';

我想知道是否有一种方法可以对解析的对象运行转换,以便在运行以下方法后得到 foo_bar 而不是获取 foo_bar(可以是任何东西)

I was wondering if there's a way to run a transformation on the parsed object so that instead of getting foo_bar, I'll get foo bar after running the following method (can be anything really)

public string Transform(string s) {
    return s.Replace("_"," ");
}

我可以在反序列化后手动更改我的 poco,但想知道什么是更清洁"的方法?

I can manually alter my poco after deserializing, but wondered what would be a "cleaner" approach?

推荐答案

您可以在反序列化根对象时转换您的 string 属性,方法是使用 自定义 JsonConverter 针对所有字符串类型值:

You can transform your string properties as you deserialize your root object by using a custom JsonConverter targeted at all string type values:

public class ReplacingStringConverter : JsonConverter
{
    readonly string oldValue;
    readonly string newValue;

    public ReplacingStringConverter(string oldValue, string newValue)
    {
        if (string.IsNullOrEmpty(oldValue))
            throw new ArgumentException("string.IsNullOrEmpty(oldValue)");
        if (newValue == null)
            throw new ArgumentNullException("newValue");
        this.oldValue = oldValue;
        this.newValue = newValue;
    }

    public override bool CanConvert(Type objectType)
    {
        return objectType == typeof(string);
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        if (reader.TokenType == JsonToken.Null)
            return null;
        var s = (string)JToken.Load(reader);
        return s.Replace(oldValue, newValue);
    }

    public override bool CanWrite { get { return false; } }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        throw new NotImplementedException();
    }
}

然后像这样使用它:

var settings = new JsonSerializerSettings { Converters = new[] { new ReplacingStringConverter("_", "") } };
var result = JsonConvert.DeserializeObject<RootObject>(json, settings);

但是请注意,如果单个字符串类型属性有自己的转换器,则直接使用 [JsonConverter(Type)],这些转换器将优先于 ReplacingStringConverter 使用.com/json/help/html/P_Newtonsoft_Json_JsonSerializerSettings_Converters.htm" rel="nofollow noreferrer">转换器列表.

Note however that if individual string-type properties have their own converters applied directly with [JsonConverter(Type)], those converters will be used in preference to the ReplacingStringConverter in the Converters list.

这篇关于对属性的 Json DeserializeObject 运行转换的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!

本站部分内容来源互联网,如果有图片或者内容侵犯您的权益请联系我们删除!

相关文档推荐

DispatcherQueue null when trying to update Ui property in ViewModel(尝试更新ViewModel中的Ui属性时DispatcherQueue为空)
Drawing over all windows on multiple monitors(在多个监视器上绘制所有窗口)
Programmatically show the desktop(以编程方式显示桌面)
c# Generic Setlt;Tgt; implementation to access objects by type(按类型访问对象的C#泛型集实现)
InvalidOperationException When using Context Injection in ASP.Net Core(在ASP.NET核心中使用上下文注入时发生InvalidOperationException)
LINQ many-to-many relationship, how to write a correct WHERE clause?(LINQ多对多关系,如何写一个正确的WHERE子句?)