问题描述
public class Simple : Form
{
public Simple()
{
Text = "Server Command Line";
Size = new Size(800, 400);
CenterToScreen();
Button button = new Button();
TextBox txt = new TextBox ();
txt.Location = new Point (20, Size.Height - 70);
txt.Size = new Size (600, 30);
txt.Parent = this;
txt.KeyDown += submit;
button.Text = "SEND";
button.Size = new Size (50, 20);
button.Location = new Point(620, Size.Height-70);
button.Parent = this;
button.Click += new EventHandler(sSubmit);
}
private void submit(object sender, KeyEventArgs e)
{
if (e.KeyCode == Keys.Enter ) {
Console.WriteLine ("txt.Text");//How do I grab this?
Submit();
}
}
}
我正在尝试从表单外部访问 txt.Text
,而谷歌也没有提供帮助.如何访问它?
I'm trying to access txt.Text
from outside the Form, and google hasn't been helpful either. How do I access it?
推荐答案
你必须在你的表单类的某处定义TextBox
的一些变量txt
,这其实是当您将 TextBox
从 Toolbox
拖放到表单上时,设计器会自动为您完成.此变量是 TextBox
的一个实例.它应该使用构造函数 TextBox()
进行初始化,并使用您在代码中所做的一些属性.您可以在表单类Simple
的范围内使用此变量.它具有属性 Text
(类型为 string
),可以修改或获取以显示.要访问属性,只需使用以下模式:[instance Name].[Property name]
You have to define some variable txt
of TextBox
somewhere in your form class, this is in fact done automatically by designer for you when you drag-n-drop a TextBox
from Toolbox
onto your form. This variable is an instance of TextBox
. It should be initialized using the constructor TextBox()
and with some properties as you did in your code. You can use this variable in the scope of the form class Simple
. It has property Text
(of type string
) which can be modified or fetched to display. To access a property, just use this pattern: [instance Name].[Property name]
public class Simple : Form
{
public Simple()
{
Text = "Server Command Line";
Size = new Size(800, 400);
CenterToScreen();
Button button = new Button();
txt = new TextBox ();
txt.Location = new Point (20, Size.Height - 70);
txt.Size = new Size (600, 30);
txt.Parent = this;
txt.KeyDown += submit;
button.Text = "SEND";
button.Size = new Size (50, 20);
button.Location = new Point(620, Size.Height-70);
button.Parent = this;
button.Click += new EventHandler(sSubmit);
}
TextBox txt;
private void submit(object sender, KeyEventArgs e)
{
if (e.KeyCode == Keys.Enter ) {
Console.WriteLine (txt.Text);
Submit();
}
}
}
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