问题描述

您好，我有以下 Xml 需要反序列化:

Hi I have the following Xml to deserialize:

<RootNode>
    <Item
      Name="Bill"
      Age="34"
      Job="Lorry Driver"
      Married="Yes" />
    <Item
      FavouriteColour="Blue"
      Age="12"
    <Item
      Job="Librarian"
       />
    </RootNote>

当我不知道键名或会有多少属性时，如何使用属性键值对列表反序列化 Item 元素?

How can I deserialize the Item element with a list of attribute key value pairs when I dont know the key names or how many attributes there will be?

推荐答案

您可以使用 XmlAnyAttribute 属性指定任意属性将被序列化和反序列化为 XmlAttribute [] 属性或使用 XmlSerializer 时的字段.

You can use the XmlAnyAttribute attribute to specify that arbitrary attributes will be serialized and deserialized into an XmlAttribute [] property or field when using XmlSerializer.

例如，如果要将属性表示为 Dictionary，则可以定义 Item 和 RootNode类如下，使用代理 XmlAttribute[] 属性将字典与所需的 XmlAttribute 数组相互转换:

For instance, if you want to represent your attributes as a Dictionary<string, string>, you could define your Item and RootNode classes as follows, using a proxy XmlAttribute[] property to convert the dictionary from and to the required XmlAttribute array:

public class Item
{
    [XmlIgnore]
    public Dictionary<string, string> Attributes { get; set; }

    [XmlAnyAttribute]
    public XmlAttribute[] XmlAttributes
    {
        get
        {
            if (Attributes == null)
                return null;
            var doc = new XmlDocument();
            return Attributes.Select(p => { var a = doc.CreateAttribute(p.Key); a.Value = p.Value; return a; }).ToArray();
        }
        set
        {
            if (value == null)
                Attributes = null;
            else
                Attributes = value.ToDictionary(a => a.Name, a => a.Value);
        }
    }
}

public class RootNode
{
    [XmlElement("Item")]
    public List<Item> Items { get; set; }
}

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