问题描述

我想将字符串2012-04-20 10:10:00+0200"格式化为具有这种格式的日期时间.所以我认为它必须是yyyy-MM-dd hh:mm:ss zzz"?

I want to format the string : "2012-04-20 10:10:00+0200" to a dateTime with this format. so I think it must be "yyyy-MM-dd hh:mm:ss zzz"?

当我尝试这个时

   // starttime =  {20/04/2012 10:10:00} without my +0200!
DateTime starttime = Convert.ToDateTime("2012-04-20 10:10:00+0200",CultureInfo.CurrentCulture);
// And this gave me a format exception : {System.FormatException: String was not recognized as a valid DateTime.
        DateTime result = DateTime.ParseExact("2012-04-20 10:10:00+0200", "yyyy-MM-dd hh:mm:ss zzz", CultureInfo.InvariantCulture);

V4Vendetta"提供的解决方案:

SOLUTION GIVEN BY "V4Vendetta" :

您应该尝试使用 DateTimeOffset 而不是 DateTime

You should try using DateTimeOffset instead of the DateTime

DateTimeOffset result = DateTimeOffset.Parse("2012-04-20 10:10:00+0200",CultureInfo.InvariantCulture);

在这里您也可以获得偏移量(2 小时)，它可以使用您的 DateTime (10:10) 值计算并获得您想要的输出 (result.DateTime + result.Offset)

Here you get the Offset (2 hrs) too which could be computed with your DateTime (10:10) value and get your desired out put (result.DateTime + result.Offset)

推荐答案

你应该尝试使用 DateTimeOffset 而不是 DateTime

You should try using DateTimeOffset instead of the DateTime

DateTimeOffset result = DateTimeOffset.Parse("2012-04-20 10:10:00+0200",CultureInfo.InvariantCulture);

在这里您也可以得到 Offset(2 小时)，这可以用您的 DateTime (10:10) 值计算并获得您想要的输出(result.DateTime+ 结果.偏移)

Here you get the Offset (2 hrs) too which could be computed with your DateTime (10:10) value and get your desired out put (result.DateTime + result.Offset)

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