问题描述
我有一个包含这三种类型的 WPF 应用程序...
- 主窗口
- UserControlZack
- 窗口模式
UserControlZack1 位于我的 WindowMain...
UserControlZack1 显示一个 WindowModal 对话框...
<上一页>部分公共类 UserControlZack...私有子 SomeButton_Click(...)'实例化对话框并以模态方式打开...暗箱 As WindowModal = New WindowModal()框.所有者 = ?????box.ShowDialog()'如果对话框被接受，则处理用户输入的数据...如果 (box.DialogResult.GetValueOrDefault = True) 那么_SomeVar = box.SomeVar...万一结束子结束类如何将 box.Owner 设置为正确的 Window，即我正在运行的 WindowMain 实例?
我不能使用 box.Owner = Me.Owner，因为'Owner' 不是 'ProjectName.UserControlZack' 的成员."
我不能使用 box.Owner = Me.Parent，因为它返回的是 Grid，而不是 Window.
我不能使用 box.Owner = WindowMain，因为'WindowMain' 是一种类型，不能用作表达式."
尝试使用
.Owner = Window.GetWindow(this)I've got a WPF application with these three types of things...
- WindowMain
- UserControlZack
- WindowModal
UserControlZack1 sits on my WindowMain...
<Window x:Class="WindowMain"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:local="clr-namespace:ProjectName"
...
Name="WindowMain">
<Grid>
...
<local:UserControlZack x:Name="UserControlZack1" ... />
...
</Grid>
</Window>
UserControlZack1 displays a WindowModal dailog box...
Partial Public Class UserControlZack
...
Private Sub SomeButton_Click(...)
'instantiate the dialog box and open modally...
Dim box As WindowModal = New WindowModal()
box.Owner = ?????
box.ShowDialog()
'process data entered by user if dialog box is accepted...
If (box.DialogResult.GetValueOrDefault = True) Then
_SomeVar = box.SomeVar
...
End If
End Sub
End Class
How do I set box.Owner to the correct Window, my running instance of WindowMain?
I cannot use box.Owner = Me.Owner, because "'Owner' is not a member of 'ProjectName.UserControlZack'."
I cannot use box.Owner = Me.Parent, because that returns a Grid, not the Window.
I cannot use box.Owner = WindowMain, because "'WindowMain' is a type and cannot be used as an expression."
Try to use
.Owner = Window.GetWindow(this)
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