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问题描述
在我的 C# 应用程序中,我有一个可以从菜单命令打开的选项对话框.
In my C# application I have an option dialog that can be opened from a menu command.
我想确保选项对话框只有一个实例(用户不能在给定时间打开多个选项窗口)而不使其成为模态.
I want to ensure that the option dialog have only one instance (user cannot open more than one option window at a given time) without making it modal.
此外,如果用户已经打开了这个窗口,并且他在菜单项中单击以再次打开它,则应用程序只会使已经可见的表单成为最顶部的窗口.
Also if the user already have this window opened, and he clicks in the menu item to open it again, the app just makes the already visible form became the top most window.
谁能指点我如何完成这些任务?
Can anyone point me directions on how accomplish these tasks?
非常感谢.
推荐答案
你需要这个表单作为属性
You will need this form as property
Form1 myForm = null;
private void Form1_FormClosed(object sender, FormClosedEventArgs e)
{
myForm = null;
}
private void ShowForm()
{
if (myForm != null)
{
myForm.BringToFront();
}
else
{
myForm = new Form1;
myForm.Show();
}
}
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