从 methodinfo 获取委托

Getting a delegate from methodinfo(从 methodinfo 获取委托)
本文介绍了从 methodinfo 获取委托的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个下拉列表,它通过检查类的方法并包括与特定签名匹配的方法来填充.问题在于从列表中获取所选项目并让委托在类中调用该方法.第一种方法有效,但我无法弄清楚第二种方法的一部分.

I have a drop down list that is populated by inspecting a class's methods and including those that match a specific signature. The problem is in taking the selected item from the list and getting the delegate to call that method in the class. The first method works, but I cannot figure out part of the second.

例如,

public delegate void MyDelegate(MyState state);

public static MyDelegate GetMyDelegateFromString(string methodName)
{
    switch (methodName)
    {
        case "CallMethodOne":
            return MyFunctionsClass.CallMethodOne;
        case "CallMethodTwo":
            return MyFunctionsClass.CallMethodTwo;
        default:
            return MyFunctionsClass.CallMethodOne;
    }
}

public static MyDelegate GetMyDelegateFromStringReflection(string methodName)
{
    MyDelegate function = MyFunctionsClass.CallMethodOne;

    Type inf = typeof(MyFunctionsClass);
    foreach (var method in inf.GetMethods())
    {
        if (method.Name == methodName)
        {
            //function = method;
            //how do I get the function to call?
        }
    }

    return function;
}

如何使第二种方法的注释掉部分起作用?如何将 MethodInfo 转换为委托?

How do I get the commented out section of the second method to work? How do I cast the MethodInfo into the delegate?

谢谢!

这是可行的解决方案.

public static MyDelegate GetMyDelegateFromStringReflection(string methodName)
{
    MyDelegate function = MyFunctionsClass.CallMethodOne;

    Type inf = typeof(MyFunctionsClass);
    foreach (var method in inf.GetMethods())
    {
        if (method.Name == methodName)
        {
            function = (MyDelegate)Delegate.CreateDelegate(typeof(MyDelegate), method);
        }
    }

    return function;
}

推荐答案

您需要调用某种形式的 Delegate.CreateDelegate(),取决于所讨论的方法是静态方法还是实例方法.

You'll need to call some form of Delegate.CreateDelegate(), depending on whether the method in question is a static or instance method.

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