本文介绍了使用动作创建任务<T, T, ... n>多个参数的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我想在包含 Action 的任务中添加多个参数.我查看了现有的堆栈溢出问题 Create a Task with an Action<T>
I want to add multiple parameter in a Task containing Action. I reviewed the existing stack-overflow question Create a Task with an Action<T>
请帮助我如何在 Task 的 Action 方法中传递多个参数
Kindly assist me how to pass multiple arguments in a Action method in a Task
Action<string, int> action = (string msg, int count) =>
{
Task.Factory.StartNew(async () =>
{ await LoadAsync(msg, count); });
};
Task task = new Task(action, ....);
动作方法是
public static async Task<string> LoadAsync(string message, int count)
{
await Task.Run(() => { Thread.Sleep(1500); });
Console.WriteLine("{0} {1} Exceuted Successfully !", message ?? string.Empty, (count == 0) ? string.Empty : count.ToString());
return "Finished";
}
请帮助我如何创建异步方法的操作以及如何将操作添加到任务中.
Kindly assist me how to Create a action of an async method and how to add the action into the Task.
推荐答案
像这样传参数就行了.
Action<string, int> action = async (msg, count) => await LoadAsync(msg, count);
Task task = new Task(() => action("", 0)); // pass parameters you want
如果你也想得到返回值
Func<string, int, Task<string>> func = LoadAsync;
Task<string> task = func("", 0); // pass parameters you want
var result = await task; // later in async method
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