本文介绍了Linq 按日期获取数据组的总和的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我的数据如下:
read_date | T1 | T2 |
15.02.2000 | 2 | 3 |
16.02.2000 | 4 | 5 |
15.03.2000 | 2 | 3 |
16.03.2000 | 5 | 4 |
我想得到 T1 和 T2 的总和，像这样:
I want to get mountly sum of T1 and T2, like this:
read_date | T1 | T2 |
02.2000 | 6 | 8 |
03.2000 | 7 | 7 |
我试着写这样的东西:
var result = from s in meter_readings.Take(10)
group s by new { s.read_date} into g
select new
{
read_date = g.Key.read_date,
T1 = g.Sum(x => x.T1),
T2 = g.Sum(x => x.T2)
};
但这并没有给出预期的数据.有没有给出数据每小时总和，每日总和等的例子.
but this does not give expected data.Is there any example to give data hourly sums, daily sums, etc.
谢谢
推荐答案
分组时只考虑年份和月份:
You should only take the year and month into account when grouping:
var result =
from s in meter_readings.Take(10)
group s by new { date = new DateTime(s.read_date.Year, s.read_date.Month, 1) } into g
select new
{
read_date = g.Key.date,
T1 = g.Sum(x => x.T1),
T2 = g.Sum(x => x.T2)
};
这篇关于Linq 按日期获取数据组的总和的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！
本站部分内容来源互联网,如果有图片或者内容侵犯您的权益请联系我们删除！