以编程方式从 XML Schema 生成测试 XML

Generate a test XML from XML Schema programmatically(以编程方式从 XML Schema 生成测试 XML)
本文介绍了以编程方式从 XML Schema 生成测试 XML的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我现在已经搜索了一些,但我无法找到以编程方式从 XML 模式自动生成数据的方法.假设我有这个 XML 模式:

I have searched for a bit now, but i'm not able to find a way to autogenerate data from a XML Schema programmatically. Lets say I have this XML schema:

<xs:element xmlns:xs="http://www.w3.org/2001/XMLSchema" name ="Persons">
  <xs:complexType>
    <xs:sequence>
      <xs:element name="Person">
        <xs:complexType>
          <xs:sequence>
            <xs:element name="FirstName" type="xs:string" />
            <xs:element name="LastName" type="xs:string" />
          </xs:sequence>
        </xs:complexType>
      </xs:element>
    </xs:sequence>
  </xs:complexType>
</xs:element> 

我可以使用 VS 函数生成示例 XML"由此创建一个 XML
有没有办法以编程方式做到这一点?

I am able to create a XML from this using the VS function "Generate Sample XML"
Is there a way to do this programmatically?

指定.我不想自己创建所有对象并以编程方式插入数据.我希望它能够像 VS 中的生成示例 XML"一样自动创建对象和属性.这样做的原因是我想更改 XSD 而不必对 xml 样本生成做任何事情.

To specify. I do not want to create all the objects and insert data programmatically myself. I would like for it to create the objects and attributes automatically just like the "Generate Sample XML" in VS. The reason for this is that i would like to change the XSD without having to do anything about xml sample generation.

推荐答案

经过一番搜索.我找到了一个实现 xml 示例生成器的 项目.我创建了一个测试解决方案并导入了这些类.然后我删除了 XmlGen.cs 文件并创建了我自己的 main 方法.输出将基于根元素.

after doing some searching. I have found a project that have implemented a xml sample generator. I created a test solution and imported the classes. Then i deleted the XmlGen.cs file and created my own main method. The output will be based on the root element.

public static void Main(string[] args)
        {
            using (var stream = new MemoryStream(File.ReadAllBytes("schema.xsd")))
            {
                var schema = XmlSchema.Read(XmlReader.Create(stream ), null);
                var gen = new XmlSampleGenerator(schema, new XmlQualifiedName("rootElement"));
                gen.WriteXml(XmlWriter.Create(@"c:	empautogen.xml"));
                Console.WriteLine("Autogenerated file is here : c:	empautogen.xml");
            }            
        }

这篇关于以编程方式从 XML Schema 生成测试 XML的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!

本站部分内容来源互联网,如果有图片或者内容侵犯您的权益请联系我们删除!

相关文档推荐

DispatcherQueue null when trying to update Ui property in ViewModel(尝试更新ViewModel中的Ui属性时DispatcherQueue为空)
Drawing over all windows on multiple monitors(在多个监视器上绘制所有窗口)
Programmatically show the desktop(以编程方式显示桌面)
c# Generic Setlt;Tgt; implementation to access objects by type(按类型访问对象的C#泛型集实现)
InvalidOperationException When using Context Injection in ASP.Net Core(在ASP.NET核心中使用上下文注入时发生InvalidOperationException)
LINQ many-to-many relationship, how to write a correct WHERE clause?(LINQ多对多关系,如何写一个正确的WHERE子句?)