本文介绍了为什么不允许在类/结构级别使用命名空间X;";?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
class C {
using namespace std; // error
};
namespace N {
using namespace std; // ok
}
int main () {
using namespace std; // ok
}
我想知道它背后的动机。
推荐答案
我不太清楚,但我猜在类范围内允许此操作可能会导致念力:
namespace Hello
{
typedef int World;
}
class Blah
{
using namespace Hello;
public:
World DoSomething();
}
//Should this be just World or Hello::World ?
World Blah::DoSomething()
{
//Is the using namespace valid in here?
}
由于没有明显的方法可以做到这一点,所以标准只是说您不能这样做。
现在,当我们讨论命名空间作用域时,这不那么令人困惑的原因是:
namespace Hello
{
typedef int World;
}
namespace Other
{
using namespace Hello;
World DoSomething();
}
//We are outside of any namespace, so we have to fully qualify everything. Therefore either of these are correct:
//Hello was imported into Other, so everything that was in Hello is also in Other. Therefore this is okay:
Other::World Other::DoSomething()
{
//We're outside of a namespace; obviously the using namespace doesn't apply here.
//EDIT: Apparently I was wrong about that... see comments.
}
//The original type was Hello::World, so this is okay too.
Hello::World Other::DoSomething()
{
//Ditto
}
namespace Other
{
//namespace Hello has been imported into Other, and we are inside Other, so therefore we never need to qualify anything from Hello.
//Therefore this is unambiguiously right
World DoSomething()
{
//We're inside the namespace, obviously the using namespace does apply here.
}
}
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