本文介绍了点 (.) 运算符和 -> 有什么区别?在 C++ 中?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
What is the difference between the dot (.) operator and -> in C++?
解决方案
foo->bar() is the same as (*foo).bar().
The parenthesizes above are necessary because of the binding strength of the * and . operators.
*foo.bar() wouldn't work because Dot (.) operator is evaluated first (see operator precedence)
The Dot (.) operator can't be overloaded, arrow (->) operator can be overloaded.
The Dot (.) operator can't be applied to pointers.
Also see: What is the arrow operator (->) synonym for in C++?
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