本文介绍了在 C++ 中将整数添加到数组中?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
Consider:
int sum(const int numbers[], const int size){
if (size == 0)
return 0;
else
return numbers[0] + sum(numbers+1, size-1);
}
This is a simple recursive function from MIT 6.096 for adding an arbitrary number of integers, and it works.
The thing I cannot understand is in the last line:
How does numbers+1 work, given numbers[] is an int array and you shouldn't be able to add an integer to an int[] constant?
解决方案
how does "numbers+1" work, given numbers[] is an int array and you shouldn't be able to add an integer to an int[] constant?
There's no int[] constant. numbers is decayed to a pointer and numbers+1 is simple pointer arithmetic applied to the parameter passed to the recursive call.
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