问题描述
在我的 Python 应用程序中,我需要编写一个正则表达式来匹配以分号 (;
).例如,它应该匹配:
In my Python application, I need to write a regular expression that matches a C++ for
or while
loop that has been terminated with a semi-colon (;
). For example, it should match this:
for (int i = 0; i < 10; i++);
...但不是这个:
for (int i = 0; i < 10; i++)
这乍一看似乎微不足道,直到您意识到左括号和右括号之间的文本可能包含其他括号,例如:
This looks trivial at first glance, until you realise that the text between the opening and closing parenthesis may contain other parenthesis, for example:
for (int i = funcA(); i < funcB(); i++);
我正在使用 python.re 模块.现在我的正则表达式看起来像这样(我已经留下了我的评论,所以你可以更容易地理解它):
I'm using the python.re module. Right now my regular expression looks like this (I've left my comments in so you can understand it easier):
# match any line that begins with a "for" or "while" statement:
^s*(for|while)s*
( # match the initial opening parenthesis
# Now make a named group 'balanced' which matches a balanced substring.
(?P<balanced>
# A balanced substring is either something that is not a parenthesis:
[^()]
| # …or a parenthesised string:
( # A parenthesised string begins with an opening parenthesis
(?P=balanced)* # …followed by a sequence of balanced substrings
) # …and ends with a closing parenthesis
)* # Look for a sequence of balanced substrings
) # Finally, the outer closing parenthesis.
# must end with a semi-colon to match:
s*;s*
这对于上述所有情况都非常有效,但是一旦您尝试使 for 循环的第三部分包含一个函数,它就会中断,如下所示:
This works perfectly for all the above cases, but it breaks as soon as you try and make the third part of the for loop contain a function, like so:
for (int i = 0; i < 10; doSomethingTo(i));
我认为它会中断,因为只要在左括号和右括号之间放置一些文本,平衡"组就会匹配包含的文本,因此 (?P=balanced)
部分不会不再起作用,因为它不会匹配(因为括号内的文本不同).
I think it breaks because as soon as you put some text between the opening and closing parenthesis, the "balanced" group matches that contained text, and thus the (?P=balanced)
part doesn't work any more since it won't match (due to the fact that the text inside the parenthesis is different).
在我的 Python 代码中,我使用了 VERBOSE 和 MULTILINE 标志,并像这样创建正则表达式:
In my Python code I'm using the VERBOSE and MULTILINE flags, and creating the regular expression like so:
REGEX_STR = r"""# match any line that begins with a "for" or "while" statement:
^s*(for|while)s*
( # match the initial opening parenthesis
# Now make a named group 'balanced' which matches
# a balanced substring.
(?P<balanced>
# A balanced substring is either something that is not a parenthesis:
[^()]
| # …or a parenthesised string:
( # A parenthesised string begins with an opening parenthesis
(?P=balanced)* # …followed by a sequence of balanced substrings
) # …and ends with a closing parenthesis
)* # Look for a sequence of balanced substrings
) # Finally, the outer closing parenthesis.
# must end with a semi-colon to match:
s*;s*"""
REGEX_OBJ = re.compile(REGEX_STR, re.MULTILINE| re.VERBOSE)
谁能建议改进这个正则表达式?太复杂了,我无法理解.
Can anyone suggest an improvement to this regular expression? It's getting too complicated for me to get my head around.
推荐答案
您可以编写一个非常简单的小程序来完成它,而无需使用正则表达式:
You could write a little, very simple routine that does it, without using a regular expression:
- 设置一个位置计数器
pos
,使其指向for
或while
之后的左括号之前. - 将左括号计数器
openBr
设置为0
. - 现在继续增加
pos
,读取相应位置的字符,当看到左括号时增加openBr
,看到右括号时减少它.这将在开始时增加一次,对于for (
"中的第一个左括号,对中间的一些括号增加和减少一些,并将其设置回0
当您的for
括号关闭时. - 所以,当
openBr
再次为0
时停止.
- Set a position counter
pos
so that is points to just before the opening bracket after yourfor
orwhile
. - Set an open brackets counter
openBr
to0
. - Now keep incrementing
pos
, reading the characters at the respective positions, and incrementopenBr
when you see an opening bracket, and decrement it when you see a closing bracket. That will increment it once at the beginning, for the first opening bracket in "for (
", increment and decrement some more for some brackets in between, and set it back to0
when yourfor
bracket closes. - So, stop when
openBr
is0
again.
停止位置是 for(...)
的右括号.现在你可以检查后面是否有分号.
The stopping positon is your closing bracket of for(...)
. Now you can check if there is a semicolon following or not.
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