问题描述
下面的程序将字符串转换为long，但根据我的理解，它也会返回错误.我所依赖的事实是，如果 strtol 成功地将字符串转换为 long，那么 strtol 的第二个参数应该等于 NULL.当我使用 55 运行以下应用程序时，我收到以下消息.
The program below converts a string to long, but based on my understanding it also returns an error. I am relying on the fact that if strtol successfully converted string to long, then the second parameter to strtol should be equal to NULL. When I run the below application with 55, I get the following message.
./convertToLong 55
Could not convert 55 to long and leftover string is: 55 as long is 55
如何从 strtol 中成功检测错误?在我的应用程序中，零是一个有效值.
How can I successfully detect errors from strtol? In my application, zero is a valid value.
代码:
#include <stdio.h>
#include <stdlib.h>
static long parseLong(const char * str);
int main(int argc, char ** argv)
{
printf("%s as long is %ld
", argv[1], parseLong(argv[1]));
return 0;
}
static long parseLong(const char * str)
{
long _val = 0;
char * temp;
_val = strtol(str, &temp, 0);
if(temp != ' ')
printf("Could not convert %s to long and leftover string is: %s", str, temp);
return _val;
}
推荐答案
大功告成.temp 本身不会为空，但是如果整个字符串被转换，它会指向一个空字符，所以你需要解引用它:
You're almost there. temp itself will not be null, but it will point to a null character if the whole string is converted, so you need to dereference it:
if (*temp != ' ')
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