本文介绍了“operator = must be a non-static member"是什么意思?意思?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我正在创建一个双链表，并重载了 operator= 以使列表中的另一个相等:
I'm in the process of creating a double-linked list, and have overloaded the operator= to make on list equal another:
template<class T>
void operator=(const list<T>& lst)
{
clear();
copy(lst);
return;
}
但是当我尝试编译时出现此错误:
but I get this error when I try to compile:
container_def.h(74) : error C2801: 'operator =' must be a non-static member
另外，如果有帮助，第 74 行是定义的最后一行，带有}".
Also, if it helps, line 74 is the last line of the definition, with the "}".
推荐答案
正如它所说的:运算符重载必须是成员函数.(在类中声明)
Exactly what it says: operator overloads must be member functions. (declared inside the class)
template<class T>
void list<T>::operator=(const list<T>& rhs)
{
...
}
另外，从 = 返回 LHS 可能是个好主意，这样你就可以链接它(比如 a = b = c) - 所以让它list
Also, it's probably a good idea to return the LHS from = so you can chain it (like a = b = c) - so make it
list<T>& list<T>::operator=....
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