C#检查是否有N个连续二进制数

using System;class MyApplication {static int count(bool []myArr, int num) {int myCount = 0, res = 0;for (int i = 0; i num; i++) {

编程学习网为您整理以下代码实例,主要实现:C#检查是否有N个连续二进制数,希望可以帮到各位朋友。

using System;

class MyApplication {

   static int count(bool []myArr, int num) {
      int myCount = 0, res = 0;
      for (int i = 0; i < num; i++) {
         if (myArr[i] == false)
            myCount = 0;
         else {
            myCount++;
            res = Math.Max(res, myCount);
         }
      }
      return res;
   }

   public static voID Main() {
      bool []myArr = {false, true, false, false, false, true, true, true};
      int num = myArr.Length;
      Console.Write("Consecutive 1's = "+count(myArr, num));
   }
}
本站部分内容来源互联网,如果有图片或者内容侵犯您的权益请联系我们删除!

相关文档推荐