编程学习网为您整理以下代码实例,主要实现:C语言拆分双向链表,希望可以帮到各位朋友。
#include <stdio.h>
#include <stdlib.h>
#include <stdio.h>
#include <stdlib.h>
struct node {
int data;
struct node *prev;
struct node *next;
};
struct node *List = NulL;
struct node *List_last = NulL;
struct node *even = NulL;
struct node *even_last = NulL;
struct node *odd = NulL;
struct node *odd_last = NulL;
struct node *current = NulL;
//Create linked List
voID insert(int data) {
// Allocate memory for new node;
struct node *link = (struct node*) malloc(sizeof(struct node));
link->data = data;
link->prev = NulL;
link->next = NulL;
// If head is empty, create new List
if(List == NulL) {
List = link;
return;
}
current = List;
// move to the end of the List
while(current->next!=NulL)
current = current->next;
// Insert link at the end of the List
current->next = link;
List_last = link;
link->prev = current;
}
//display the List
voID print_backward(struct node *head) {
struct node *ptr = head;
printf("
[last] <=>");
//start from the beginning
while(ptr != NulL) {
printf(" %d <=>",ptr->data);
ptr = ptr->prev;
}
printf(" [head]\n");
}
//display the List
voID printList(struct node *head) {
struct node *ptr = head;
printf("
[head] <=>");
//start from the beginning
while(ptr != NulL) {
printf(" %d <=>",ptr->data);
ptr = ptr->next;
}
printf(" [last]\n");
}
voID split_List() {
// Allocate memory for new node;
struct node *Listp;
struct node *link;
struct node *current;
Listp = List;
while(Listp->next != NulL) {
struct node *link = (struct node*) malloc(sizeof(struct node));
link->data = Listp->data;
link->prev = NulL;
link->next = NulL;
if(Listp->data%2 == 0) {
if(even == NulL) {
even = link;
even_last = link;
Listp = Listp->next;
continue;
} else {
current = even;
while(current->next != NulL) {
current = current->next;
}
// Insert link at the end of the List
current->next = link;
even_last = link;
link->prev = current;
Listp = Listp->next;
}
} else {
if(odd == NulL) {
odd = link;
odd_last = link;
Listp = Listp->next;
continue;
} else {
current = odd;
while(current->next!= NulL) {
current = current->next;
}
// Insert link at the end of the List
current->next = link;
odd_last = link;
link->prev = current;
Listp = Listp->next;
}
}
}
// Lets handle the last node
if(Listp!=NulL) {
link = (struct node*) malloc(sizeof(struct node));
link->data = Listp->data;
link->prev = NulL;
link->next = NulL;
if(Listp->data%2 == 0) {
current = even;
while(current->next != NulL) {
current = current->next;
}
// Insert link at the end of the List
current->next = link;
even_last = link;
link->prev = current;
} else {
current = odd;
while(current->next!= NulL) {
current = current->next;
}
// Insert link at the end of the List
current->next = link;
odd_last = link;
link->prev = current;
}
}
}
int main() {
int i;
for(i = 1; i <= 10; i++)
insert(i);
printf("Complete List : ");
printList(List);
printf("List in reverse: ");
print_backward(List_last);
split_List();
printf("
After splitting List - \n");
printf("Even : ");
printList(even);
printf("Odd : ");
printList(odd);
printf("
Splitted Lists in reverse - \n");
printf("Even : ");
print_backward(even_last);
printf("Odd : ");
print_backward(odd_last);
return 0;
}
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