将换行符和制表符等字符转换为可见的转义序列

#include stdio.h#define MAXLINE 1000int getchars(char line[], int maxline);void escape(char s[], char t[]);

编程学习网为您整理以下代码实例,主要实现:将换行符和制表符等字符转换为可见的转义序列,如\n和\t,希望可以帮到各位朋友。

#include <stdio.h>

#define MAXliNE 1000

int getchars(char line[], int maxline);
voID escape(char s[], char t[]);
voID unescape(char s[], char t[]);

int main(voID){
    char t[MAXliNE] = "this is \na \ttest\" test \v test \r ";
    char s1[MAXliNE];
    char s2[MAXliNE];

    escape(s1, t);
    printf("\nescape result:\n%s\n", s1);

    unescape(s2, s1);
    printf("unescape result:\n%s\n", s2);

    return 0;
}
voID escape(char s[], char t[]){
    int i, j;

    for (i = 0, j = 0; t[i] != '\0'; ++i) {
        switch (t[i]) {
        case '\n':
            s[j++] =  '\\';
            s[j++] =  'n';
            break;
        case '\t':
            s[j++] =  '\\';
            s[j++] =  't';
            break;
        case '\v':
            s[j++] =  '\\';
            s[j++] =  'v';
            break;
        case '\b':
            s[j++] =  '\\';
            s[j++] =  'b';
            break;
        case '\r':
            s[j++] =  '\\';
            s[j++] =  'r';
            break;
        case '\f':
            s[j++] =  '\\';
            s[j++] =  'f';
            break;
        case '\a':
            s[j++] =  '\\';
            s[j++] =  'a';
            break;
        case '\\':
            s[j++] =  '\\';
            s[j++] =  '\\';
            break;
        case '\?':
            s[j++] =  '\\';
            s[j++] =  '\?';
            break;
        case '\'':
            s[j++] =  '\\';
            s[j++] =  '\'';
            break;
        case '\"':
            s[j++] =  '\\';
            s[j++] =  '\"';
            break;
        default:
            s[j++] = t[i];
            break;
        }
    }
    s[j] = '\0';
}

voID unescape(char s[], char t[])
{
    int i, j;

    for (i = 0, j = 0; t[i] != '\0'; ++i) {
        if (t[i] == '\\') {
            switch (t[++i]) {
            case 'n':
                s[j++] =  '\n';
                break;
            case 't':
                s[j++] =  '\t';
                break;
            case 'v':
                s[j++] =  '\v';
                break;
            case 'b':
                s[j++] =  '\b';
                break;
            case 'r':
                s[j++] =  '\r';
                break;
            case 'f':
                s[j++] =  '\f';
                break;
            case 'a':
                s[j++] =  '\a';
                break;
            case '\\':
                s[j++] =  '\\';
                break;
            case '\?':
                s[j++] =  '\?';
                break;
            case '\'':
                s[j++] =  '\'';
                break;
            case '\"':
                s[j++] =  '\"';
                break;
            // actually, cases below should never happen if the input string is correct.
            case '\0':
            default:
                s[j++] = '\\';
                --i;
                break;
            }
        } else {
            s[j++] =  t[i];
        }
    }
    s[j] = '\0';
}
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