问题描述
我有两个窗口:parent 和 popup.显然 parent 有对 popup 的引用.现在在 popup 我有一个函数说
I have two windows: the parent and the popup. Obviously parent has a reference to popup. Now in popup I have a function say
function test() { alert('test'); }
我想在 parent 中调用这个函数，类似于 popup.test();.有没有办法做到这一点?我确实知道如何反过来做.只是声明
and I want to call this function in parent, something like popup.test();. Is there a way to do that? I do know how to do that the other way around. Just declaring
window.test = function() { alert('test'); }
并在弹出窗口中调用 window.opener.test(); 工作正常.但是，这在我的情况下不起作用(我认为因为 window.opener 对象是一个引用，但是 window.open 和 window 在 popup 并不真正相关).有什么想法吗?
and calling window.opener.test(); in popup works fine. However this does not work in my case (I think because the window.opener object is a reference, but window.open and window in popup are not really related). Any ideas?
推荐答案
这实际上取决于您为弹出窗口定义函数的上下文.假设您将函数/数据附加到弹出窗口的 window 对象，您可以从 window.open 返回的窗口句柄(窗口句柄 是弹出窗口的window对象):
It really depends on the context where you defined the function for the popup window. Assuming you attached the functions/data to the window object of the popup window, you can access it from the window handle returned by window.open (the window handle is the window object for the popup):
var w = window.open(somelocation,''); //has a function on `window` called "test"
w.test();
我假设您了解安全沙箱如何用于弹出窗口
这篇关于从父窗口中的子窗口运行函数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！