本文介绍了围绕另一个 CGPoint 旋转一个 CGPoint的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
好的,所以我想将 CGPoint(A) 围绕 CGPoint(B) 旋转 50 度,有什么好的方法吗?
Okay so I want to rotate CGPoint(A) 50 degrees around CGPoint(B) is there a good way to do that?
CGPoint(A) = CGPoint(x: 50, y: 100)
CGPoint(A) = CGPoint(x: 50, y: 100)
CGPoint(B) = CGPoint(x: 50, y: 0)
CGPoint(B) = CGPoint(x: 50, y: 0)
这是我想做的:
推荐答案
这真的是一道数学题.在 Swift 中,你想要这样的东西:
This is really a maths question. In Swift, you want something like:
func rotatePoint(target: CGPoint, aroundOrigin origin: CGPoint, byDegrees: CGFloat) -> CGPoint {
let dx = target.x - origin.x
let dy = target.y - origin.y
let radius = sqrt(dx * dx + dy * dy)
let azimuth = atan2(dy, dx) // in radians
let newAzimuth = azimuth + byDegrees * CGFloat(M_PI / 180.0) // convert it to radians
let x = origin.x + radius * cos(newAzimuth)
let y = origin.y + radius * sin(newAzimuth)
return CGPoint(x: x, y: y)
}
有很多方法可以简化这一点,这是对 CGPoint
的扩展的完美案例,但为了清楚起见,我将其保留为冗长.
There are lots of ways to simplify this, and it's a perfect case for an extension to CGPoint
, but I've left it verbose for clarity.
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